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2 years ago

If you have 6 moles of CH4 how many moles of H2O can be produced

Chemistry

1 answer:

nadya68 [22]2 years ago

8 0

Answer:

Explanation:

CH4 + 2O2 --> CO2 + 2H2O

1mol generates 2 moles of H2O

Therefore 6 Moles produce 12 moles of H2O

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The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat

user100 [1]

<u>Answer:</u> The heat required for the process is 4.24 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of benzene = 24.8 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

$\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat absorbed = ?

n = number of moles = 0.318 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = 30.7 kJ/mol

Putting values in above equation, we get:

$30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ$

Hence, the heat required for the process is 4.24 kJ

6 0

3 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.1 g of butane is m

m_a_m_a [10]

Answer:

12.44 g

Explanation:

2C4H10 + 13O2 = 8CO2 + 10H2O

n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).

n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).

Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.

mass of CO2 produced =

M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol

M = 0.5656/2 * 44

M = 0.2828 * 44

M = 12.44 of CO2

5 0

2 years ago

Which of the following is a hypothesis for an experiment measuring solubility of sodium sulfate?

SCORPION-xisa [38]

A would be a hypothesis

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2 years ago

Which property is better explained by the band theory than by the sea-of-electrons model?

Sonbull [250]

Luster is the correct answer.

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2 years ago

Write the mechanism for the two steps of the hydroboration/oxidation reaction of indene

iVinArrow [24]

It's difficult to write it down, but I'll attach you a good example of hydroboration of indene. I hope you'll find it helpful.

5 0

3 years ago