Answer:
Step-by-step explanation:
2(x + 15)⁰ + (3x + 20)⁰=180⁰
2x + 30⁰ + 3x + 20⁰=180⁰
2x + 3x + 30⁰ + 20⁰=180⁰
5x + 50⁰ - 50⁰=180⁰-50⁰
5x=130⁰
5x/5=130⁰/5
x=26⁰
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Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.
Let the number of toys Oleg has = x
Let the number of toys Sasha has = y
Let the number of toys Dima has = z
Sasha had twice as many toys as Oleg
So y = 2*x= 2x
Dima had 40 more toys than Oleg.
z = x + 40
Oleg, Sasha, and Dima shared 600 toys
x + y + z= 600
We know y=2x and z=x+40
Replace it for y and z
Subtract 40 on both sides
Divide by 4 on both sides
Oleg had 140 toys
Answer:
The answer is B
It's the same because it's still negative
1507 are the different ways can 5 baseball players and 4 basketball players be selected from 12 baseball players and 13 basketball players
<em><u>Solution:</u></em>
Given that,
5 baseball players and 4 basketball players be selected from 12 baseball players and 13 basketball players
This is a combination problem
Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter
<em><u>The formula is given as:</u></em>
Where n represents the total number of items, and r represents the number of items being chosen at a time
<em><u>Let us first calculate 5 baseball players from 12 baseball players</u></em>
Here, n = 12 and r = 5
<em><u>For a number n, the factorial of n can be written as:</u></em>
Therefore,
<em><u>Similarly, 4 basketball players be selected 13 basketball players</u></em>
n = 13 and r = 4
Similarly we get,
<em><u>Thus total number of ways are:</u></em>
Thus there are 1507 different ways