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Neko [114]
3 years ago
12

Which cross could produce a child with blood type A?

Biology
2 answers:
Strike441 [17]3 years ago
8 0

Answer:

d. Ao x oo

Explanation:

The other crosses with A would all result in complete dominance because the alleles (other than A) from the other parent are dominant. Because option D. crosses a h o m o zygous parent with a recessive trait, the cross could produce a child with blood type A.

shusha [124]3 years ago
6 0
Yeah the other person is right it’s D
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How many new volumes would each new cell contain whenever a cell splits?
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Answer:

a) The expected phenotype of the F1 plants is 100% RrBb, red kernels.

b) The expected phenotypic classes in the F2 are: 9:3:3:1

   9/16 R-B-, 3/16 rrB-, 3/16 R-bb,  1/16 rrbb

   Proportions 9:6:1.

9/16 Red kernel (R-B-), 6/16 Brown kernel (rrB- + R-bb), 1/16 White kernel (rrbb)    

Explanation:

<u>Available data:</u>

  • red kernel: R-B-
  • brown kernel: R-bb or rrB-
  • white kernel: rrbb

1º Cross)  RRBB      x      rrbb

F1)             100% RrBb (red kernels)

2ºCross)   RrBb       x       RrBb

Gametes)  RB                   RB

                  Rb                   Rb

                  rB                    rB

                  rb                    rb

Punnet Square)      RB           Rb         rB         rb

                 RB      RRBB      RRBb     RrBB     RrBb

                 Rb      RRBb      RRbb     RrBB     Rrbb

                 rB       RrBB       RrBb      rrBB      rrBb

                 rb       RrBb       Rrbb       rrBb     rrbb

F2)  Phenotypic classes:

       <em>9/16 R-B-</em>

<em>        3/16 rrB-</em>

<em>        3/16 R-bb</em>

<em>        1/16 rrbb</em>

      Phenotypic proportions:

      <em>9/16 Red kernel (R-B-)</em>

<em>       6/16 Brown kernel (rrB- + R-bb)</em>

<em>       1/16 White kernel (rrbb)         </em>                      

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