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3 years ago

In the expression, what is the variable, the coefficient, and the constant?

Mathematics

1 answer:

kirill [66]3 years ago

7 0

Step-by-step explanation:

In expression:25w+55

variable=w

cofficient = coefficient of variable (w)=25

constant=55

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Use one of the triangles to approximate PQ in the triangle below.

s2008m [1.1K]

Answer:

The answer is B 5.4 units

Step-by-step explanation:

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2 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

1 year ago

Shelia rolled a number cube numbered 1 through 6 tossed coin for heads ,h or tails,t. Which List Represent All the Possible outc

scZoUnD [109]

Answer: c

Explanation:

7 0

3 years ago

During a school race, Sonic ran around the entire track 5 times in 10 seconds. Everyone was shocked by his speed, which was equa

Aleonysh [2.5K]

Step-by-step explanation:

there is no diagram here.

I assume that the race track is a rectangle in the middle and two half-circles at the left and right ends, and that the length of the rectangle is D = 2R. which makes the rectangle actually a square, as the width is the diameter of the (half-)circles, which is also 2R.

Sonic ran the track 5 times in 10 seconds with a speed of 321 m/s.

that means he ran 10×321 m in 10 seconds = 3210 m.

so, 5 times the track is 3210 m, which means that the track itself is 3210/5 = 642 m long.

and based on the assumptions above the track consists of 2 times the length of the rectangle (or square), and the full circumference of a circle with radius R (2 half-circles make one full circle).

we know the formula for the circumference of a circle :

2×pi×radius

so, we have then

642 = 2×2R + 2×pi×R = R×(4 + 2×pi)

R = 642 / (4 + 2×pi) = 62.43201701...

and when using the requested "cut-off" pi = 3.14, we get

R = 642 / (4 + 2×3.14) = 62.45136187...

and that is rounded 62.5

so, the second answer option is correct.

7 0

2 years ago

Read 2 more answers

Can someone answer number 12 for me

docker41 [41]

Answer:

Number 12

Step-by-step explanation:

Number 12 :))

4 0

1 year ago