Question

What is the phase shift of y = sin(1/2 x - pi/2)?

Answer 1

Answer:

π

Step-by-step explanation:

The standard form of the sine function is

y = a sin(bx + c)

where a is the amplitude, period = $\frac{2\pi }{b}$ and

phase shift = - $\frac{c}{b}$

here b = $\frac{1}{2}$, c = - $\frac{\pi }{2}$

phase shift = - $\frac{-\frac{\pi }{2} }{\frac{1}{2} }$

= $\frac{\pi }{2}$ × 2 = π