All categories

3 years ago

Multiply (x - 4)(x - 3) PLZZZ get it RIGHT, SHOW YOUR WORK,AND NO LINKS PLZ!

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

Step-by-step explanation:

x²-3x-4x+12

x²-7x+12

Pepsi [2]3 years ago

3 0

Answer:

Step-by-step explanation:

(x - 4) (x - 3)

x^2 - 3x - 4x + 12 (you distribute x in (x-4) to each of the terms x and -3 and multiply them. x*x is x^2 and x*(-3) is -3x. Then, you distribute -4 in (x-4) to each of the terms x and -3 and multiply them. -4*x is -4x and -4*-3 is 12)

x^2 - 7x + 12 (B)

You might be interested in

Solve the system by the elimination method.<br> 16x-3y=-1<br> -8x+y=3

mojhsa [17]

Send me your email I will send the working.

The answers:
x = 1
y = -5

7 0

3 years ago

Unit 3 homework 6 Gina Wilson

Sonja [21]

Answer:

5) The equation of the straight line is 2 x - y + 1 =0

6) The equation of the straight line is x + y -5 =0

7) The equation of the straight line is 5 x + 6 y - 24 =0

8) The equation of the straight line is x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,3) , ( -3,-5)

$m = \frac{-5-3 }{-3-1 } = \frac{-8}{-4} = 2$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 3 = 2 ( x - 1 )$

y = 2x - 2 +3

2 x - y + 1 =0

The equation of the straight line is 2 x - y + 1 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,4) , ( 6,-1)

$m = \frac{-1-(4) }{6-1 } = \frac{-5}{5} = -1$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 1 = -1 ( x - 4 )$

y - 1 = - x +4

The equation of the straight line is x + y -5 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-12 , 14) , ( 6,-1)

$m = \frac{-1-(14) }{6+12 } = \frac{-15}{18} = \frac{-5}{6}$

$y - 14 = \frac{-5}{6} ( x - (-12) )$

6( y - 14 ) = - 5 ( x +12 )

6 y - 84 = - 5x -60

5 x + 6 y -84 + 60 =0

5 x + 6 y - 24 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-4 , -2) , ( 4 , 0)

$m = \frac{0+2}{4 +4} = \frac{2}{8} = \frac{1}{4}$

$y - (-2) =\frac{1}{4} ( x - (-4) )$

4 ( y + 2) = x + 4

x - 4 y -4 =0

The equation of the line y = 3x + 6 is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒ 3x + y + k =0

⇒ 12 + 7 + k =0

⇒ k = -19

The equation of the parallel line is 3x + y -19 =0

4 0

3 years ago

How can I solve 4x^2 + 12x > -x -3

Damm [24]

He have the following:

$4x^2+12x>-x-3$

solving:

$\begin{gathered} 4x^2+12x+x+3>-x-3+x+3 \\ 4x^2+13x+3>0 \\ \text{factoring} \\ (4x+1)(x+3)>0 \\ (4x+1)>0\rightarrow4x+1-1>-1\rightarrow\frac{4x}{4}>-\frac{1}{4}\rightarrow x>-\frac{1}{4} \\ (x+3)$

5 0

1 year ago

find the measure of the arc or angle indicated. assume that lines which appear to be diameters are actual diameters just enter t

konstantin123 [22]

Answer:

I think D

if wrong correct me plssssssss

have a nice day

And good luck if you have exam

#Captainpower

8 0

3 years ago

Add (2x+5) + (3x-7)<br> plsssssss SBUIAXSBADJASN

MArishka [77]

2x+3x= 5x
5-7= -2

so its 5x-2 since all like terms are added

6 0

3 years ago