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r-ruslan [8.4K]

3 years ago

15

If there are 25 students in a class in which 5 of the 11 guys wear glasses and 6 out of the 14 girls wear glasses- what is the p

robability that one of the students in the class is a guy that he wears glasses?

1 answer:

DochEvi [55]3 years ago

3 0

Answer:

6 out of 25

Step-by-step explanation:

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Find the difference between <br> 10 and −25 (Hint: Subtract the numbers in the order given.)

gladu [14]

The difference is -15

7 0

3 years ago

Create a storyline (word problem) for the real-world graph below.

snow_lady [41]

Answer:

Y would equal X on Day 65

Step-by-step explanation:

Im guessing by looking at the chart

7 0

2 years ago

Read 2 more answers

√7.5×√3.5 step and answer

irina1246 [14]

Answer:

√105/2

Step-by-step explanation:

Given the surd expression √7.5×√3.5, this can also be expressed as;

√7.5×√3.5

= √75/10 × √35/10

= √(75×35)/10×`10

=√105×25/100

= 5√105/√100

=5√105/10

=√105/2

Hence the required expression a √105/2

4 0

3 years ago

If two angles are supplementary , they must

-BARSIC- [3]

If the two angles are supplementary, they must equal 180 degrees

7 0

3 years ago

Read 2 more answers

Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at

sweet [91]

Answer: The answer is 35 minutes.

Step-by-step explanation: Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

$d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.$

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

$d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.$

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

$d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.$

Now, difference between Lars and Gavin's rate of runnings is

$\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.$

Therefore, the time taken by Lars to reach Gavin is given by

$t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.$

Thus, the required time is 365 minutes.

6 0

3 years ago