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1 year ago

Without considering other forces such as friction what is the net force in this problem?

Mathematics

2 answers:

aleksley [76]1 year ago

8 0

Answer:

25 N to the left

Step-by-step explanation:

The net force is equal to the differences in magnitudes of the forces acting on it.

Take the left direction to be positive (+) and right direction to be negative (-).

Solving :

Net Force = Force (left) - Force (right)

Net Force = 10 + 20 - 5

Net Force = 30 - 5

Net Force = 25 N to the left

sineoko [7]1 year ago

7 0

F_net

F1+F2+F3
10+20-5
30-5
25N

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2 t-shirts and 3 hats costs £12.

Mariana [72]

Answer:

Cost of tshirt = £7.29

Cost of what = £0.86

Step-by-step explanation:

2t +3h = 12; 10t + 15h = 60

5t + 4h =33; 10t + 8h = 66

15h -8h = -6

7h = -6; h = -6/7; h = 0.86

2t +3(-6/7) =12

14t -18 = 84

14t = 102; t = 102/ 14; t=7.29

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2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago

Nylan robotics has a budget of 99.00 to buy sprockets axles and gears. If they spend 2/3 of the budget on sprockets how much mon

grin007 [14]

99*1/3=33

so 2/3=66

so 33 dollars remain

8 0

2 years ago

Read 2 more answers

Write (9,-4) and (1,6) in slope intercept form,

vesna_86 [32]

Answer:

y = -5/4x + 7 1/4

Step-by-step explanation:

The difference in y (10) over the difference in x (8)

7 0

1 year ago

How do you name a vector?

Llana [10]

You can name a vector by its length and direction

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2 years ago