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noname [10]
3 years ago
15

Find the value of each variable. Simplify your answer as much as possible.

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question an attached file is missing, which can be defined as follows please find it.

In part (i):

In the \triangle ABC, the side BD bisector of \angle B:

according to bisector theorem:

\to \frac{6}{x}=\frac{4}{6}\\\\\to 6 \times 6 = 4 \times x\\\\\to \frac{6 \times 6}{4} = x\\\\\to x =\frac{36}{4} \\\\\to x =9 \\\\

In point (ii):

In the \triangle ADB, the side BD bisector of \angle A:

according to bisector theorem:

\to \frac{8}{4}=\frac{6-y}{y}\\\\\to \frac{2}{1}=\frac{6-y}{y}\\\\ \to 2 =\frac{6-y}{y}\\\\\to 2y = 6-y\\\\ \to 2y+y 6\\\\ \to 3y =6 \\\\ \to y = \frac{6}{3}\\\\\to y= 2

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We can solve by elimination. Eliminate one of the variables by adding OR subtracting the entire equations. I will add.

.     x + y = 100

<u>+    x - y = 80</u>       y + - y = y - y = 0; The variable is eliminated

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Substitute x = 90 into one of the equations.

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90 + y = 100  Isolate y by subtracting 90 from both sides

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y = 10

Find xy = ?? by substituting y for 10 and x for 90.

xy = (90)(10) = 900

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