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noname [10]
3 years ago
15

Find the value of each variable. Simplify your answer as much as possible.

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question an attached file is missing, which can be defined as follows please find it.

In part (i):

In the \triangle ABC, the side BD bisector of \angle B:

according to bisector theorem:

\to \frac{6}{x}=\frac{4}{6}\\\\\to 6 \times 6 = 4 \times x\\\\\to \frac{6 \times 6}{4} = x\\\\\to x =\frac{36}{4} \\\\\to x =9 \\\\

In point (ii):

In the \triangle ADB, the side BD bisector of \angle A:

according to bisector theorem:

\to \frac{8}{4}=\frac{6-y}{y}\\\\\to \frac{2}{1}=\frac{6-y}{y}\\\\ \to 2 =\frac{6-y}{y}\\\\\to 2y = 6-y\\\\ \to 2y+y 6\\\\ \to 3y =6 \\\\ \to y = \frac{6}{3}\\\\\to y= 2

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Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo
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Answer:

\displaystyle y-5=-\frac{10}{9}(x+6)

Or:

\displaystyle y+5=-\frac{10}{9}(x-3)

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

y-y_1=m(x-x_1)

Thus, first, we need to find the slope. We can use the slope formula:

\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

\displaystyle y-(5)=-\frac{10}{9}(x-(-6))

Or, fully simplified:

\displaystyle y-5=\frac{-10}{9}(x+6)

Using the other point, we will acquire:

\displaystyle y-(-5)=-\frac{10}{9}(x-(3))

Or, simplified:

\displaystyle y+5=-\frac{10}{9}(x-3)

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Is k6= a solution or non solution
mrs_skeptik [129]
I think it will be a solution. Hope it help!
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