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True [87]
3 years ago
7

Please explain how you got the answer!

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

16

Step-by-step explanation:

1250/ 80 = 125/8 ≈ 15.6 rounds up to 16

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Hannah loves to read. She read 2 pages of a book in a bookstore before she bought it. She graphs her progress on the book since
Kisachek [45]

The answer is: <em>2 pages per minute</em>

6 0
3 years ago
4 divided by 2/5<br><br> 2.4 divided by 3/5
Sav [38]

Answer:

4 divided by 2/5 is 10

2.4 divided by 3/5 is 4

I hope I helped ^^

7 0
3 years ago
Zekia divides 6 cups of fruit juice equally among 8 friends. 2 of her friends don't drink the juice. How much is leftover? Thank
BlackZzzverrR [31]
6 = 8f - 2f
6 = 6f
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5 0
4 years ago
Read 2 more answers
Jessi sold half her comic books. Then, she bought 9 more. She now has 11 total. How many did she begin with?
Alex Ar [27]

Answer:X+9=11

9-9|11-9

X=2

Step-by-step explanation:When the beginning number is unknown we use “x” to be a place holder. If she got 9 more books we would add 9 to the equation. Finally if 11 is the total, the end of the equation would equal 11.

6 0
4 years ago
Please explain I really need help
velikii [3]

Answer:

1. 1343 years

2. 9 hours

3. 39 years

Step-by-step explanation:

1. Given, half-life of carbon = 5730 years.

∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121

If N₀ = 100 then N = 85

Formula:- N = N₀*e^(-λt)

∴ 85 = 100 * e^(-0.000121t)

∴㏑(-0.85)=-0.000121t

∴ t = 1343 years

2. Given half-life of aspirin = 12 hours

λ = 0.693/12 = 0.5775

Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.

∴ 70 = 100 *e^(-0.05775t)

0.70 = e^(-0.05775t)

㏑(0.70) = -0.05775t

∴ t = 9 hours

3.  The population of the birds as as A=A₀*e^(kt)

Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.

The population is 1400 when f = 0, And it is 1000 when f = 5

We can write the following equation :

1400 = 1000e^(5t).

∴1400/1000 = e^(5k)

∴ k = ㏑(1.4)/5

We need to find x such that 1400/100 = e^(xk)

14 = e^(xk)

∴ x = 39 years

5 0
3 years ago
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