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WITCHER [35]
3 years ago
7

Please help me, I’m struggling

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

28\sqrt{6}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

\sqrt{96}

= \sqrt{16(6)}

= \sqrt{16} × \sqrt{6}

= 4\sqrt{6}

Then

7\sqrt{96}

= 7 × 4\sqrt{6}

= 28\sqrt{6}

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I need help putting correct answers in the yellow boxes.
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Answer:

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Step-by-step explanation:

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2 years ago
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Answer:

16

Step-by-step explanation:

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3 years ago
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ELEN [110]
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3 years ago
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In the figure, AngleRQS Is-congruent-to AngleQLK. 3 lines are shown. Lines S P and K N are parallel. Line R M intersects line S
stepan [7]

Answer:

x=108

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠RQS≅m∠QLK -----> by corresponding angles

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so

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substitute

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