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qwelly [4]
3 years ago
10

Solve the system of equations using elimination

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0

Answer:

(1, 3).

Step-by-step explanation:

x + 2y = 7

3x - 2y = -3

Adding the 2 equations will eliminate y:

4x  = 4

x = 4/4

x = 1

Plug x = 1 into the first equation:

1 + 2y = 7

2y = 6

y = 3.

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Can someone please explain 10 3/4 - 6 4/4 ??
motikmotik

3 3/4 is the answer

10 3/4 --- 43/4

6 4/4--- 7 or  28/4

43/4- 28/4=  15/4

15/4 simplified is 3 3/4

4 0
3 years ago
Read 2 more answers
1000 grams decreased by 94%
gregori [183]
subtract\ 94\%\ of\ 1000\ from\ 1000\\\\1000-94\%*10000=1000-0.94*1000=1000-940=60\\\\
1000\ grams\ decreased\ by\ 94\%\ is\ 60.
3 0
3 years ago
Solve r = 1/2m^2p for p
hoa [83]
You just have to arrange the equation such that the p is the only term at the left hand side of the equation. Express it in terms of r and m. 

r = 1/2*m²*p
Divide both left and right hand side equations by 1/2*m²
p = r/(1/2 *m²)
Take the reciprocal of 1/2 and multiply it. The final answer is:
p = 2r/m²
7 0
3 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

8 0
3 years ago
Copy and complete the table of each values for each equation
Aleksandr-060686 [28]

Step-by-step explanation:

Given function is y = –x.

Substitute the values of x in the function and find the values of y.

y = –x

At x = –2,

y = –(–2) = 2

At x = –1,

y = –(–1) = 1

At x = 0,

y = –(0) = 0

At x = 1,

y = –1(1) = –1

At x = 2,

y = –(2) = –2

Now, substitute the values of y in the table.

The image of the table is attached below.

8 0
3 years ago
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