Solve the system of equations using elimination

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer:

(1, 3).

Step-by-step explanation:

x + 2y = 7

3x - 2y = -3

Adding the 2 equations will eliminate y:

4x = 4

x = 4/4

x = 1

Plug x = 1 into the first equation:

1 + 2y = 7

2y = 6

y = 3.

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Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.

SSSSS [86.1K]

Answer:

$\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}$

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

$-x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}$