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3 years ago

Pls help me a solve this one math problem:(

Mathematics

1 answer:

Phantasy [73]3 years ago

8 0

Answer:

2 units up for every one unit across, or just simply 2

Step-by-step explanation:

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Suppose a family starts out 50 miles from home at time t = 0. They travel away from home at a constant speed of 45 miles an hour

skelet666 [1.2K]

50 miles, t=0 is the start
45 miles each 1 hour

A. d= 45•t+50

3 0

3 years ago

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At the building site there are 16 pallets with sacks of cement the total weight of all the pallets and cement is 4856 pounds eac

inysia [295]

The first thing we must do for this case is to define a variable.
We have then:
x: weight of each pallet with cement
We then have the following equation:
16x = 4856
Clearing x we have:
x = (4856) / (16)
x = 303.5 punds
Answer:
each pallet with cement weigh:
x = 303.5 punds

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3 years ago

Solve problem: 8-6•4+10/2

Westkost [7]

Answer: -11

Step-by-step explanation: Hope this helps

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3 years ago

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A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$