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Rainbow [258]
3 years ago
8

Solve using elimination x-2y=10 and x+3y=5

Mathematics
1 answer:
Zina [86]3 years ago
6 0
Multiply the equation (x-2y=10) by -1
-x+2y=-10
x+3y=5
The x’s cancel out
2y=-10
3y=5
Combine
5y=-5
Divide both sides by 5
y=-1
Plug in y to either original equation
x-2(-1)=10
x+2=10
Subtract 2 from both sides
x=8, y=-1
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4 years ago
7/8 = ?/48<br> A.13<br> B. 1<br> C. 42<br> D. 6
Ugo [173]

Hi Brainiac


7/8 =?/48

Let's replace the unknown place by x

7/8 = x/48

Cross multiply

(7)(48)= (X)(8)

336 = 8x

Flip it

8x = 336

Divide both sides by 8

8x/8 = 336/8

x= 42

The answer is C



Now if you wanna see if the answer is good just replace 42 in blank space

7/8 = 42/48

Now didivde 7 by 8 and divide 42 by 48

7/8= 0.875

42/48= 0.875


The answer C is correct


I hope that's help:)


If you have questions please let me know :)

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4 years ago
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3 years ago
List the first ten multiples of number 4
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5 0
4 years ago
Read 2 more answers
Help with this question !
Genrish500 [490]
Statements                                           Reasons
1. Write all the given as you did            1. Given
2. <DBA and <DBC are right angles     2. Def of perpendicular lines
3. m<DBA = 90                                     3. Def of right angle
    m<DBC = 90
4. m<DBA = m<DBC                             4. Substitution
5. m<DBA = m<1 + m<3                       5. Angle addition postulate
    m<DBC = m<2 + m<4
6. m<1 + m<3 = m<2 + m<4                  6. Substitution
7. m<3 = m<4                                        7. Subtraction prop of equality
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4 years ago
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