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Ket [755]
2 years ago
15

Want to play blooket code is 587721

Mathematics
2 answers:
Artyom0805 [142]2 years ago
8 0

Answer:

Step-by-step explanation:

wariber [46]2 years ago
4 0

Answer:

Bleh code doesn't work...

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Find x in the triangle below. Round your answer to the nearest tenth.
jonny [76]

Answer:

Step-by-step explanation:

Remark

  • x is opposite the 90 degree angle. It is the hypotenuse.
  • 13 makes up the 57 degree angle. It is the side adjacent.
  • The adjacent side and the hypotenuse define the cos(theta).

Formula

cos(theta) = adjacent side / hypotenuse

Givens

Theta = 57 degrees

Hypotenuse = x

Side adjacent = 13

Solution

  • Cos(57) = 13 / x         Multiply both sides by x
  • x*cos(57) = 13           Divide by cos(theta)
  • x = 13/cos(57)
  • x = 13 / cos(57)
  • cos(57) = 0.5446
  • x = 13/ 0.5446
  • x = 23.87
6 0
2 years ago
Pls guys help me pls ​
galina1969 [7]

Answer:

x < 5

I think the answer is A

8 0
2 years ago
If f(x) = -3x+1 then f^-1(x) =
elena55 [62]

Answer:

please mark me brainliesf if it helps you

f(x) = -3x+1

or, y = -3x + 1

Interchanging the position of x and y, we get,

x = -3y +1

or, 3y = 1 - x

or, y = 1 - x /3

: . f^-1(x) = 1-x / 3

8 0
2 years ago
6 QUESTIONS!! Simplify, thankyou!!
dezoksy [38]

Answer: Check explanation

Step-by-step explanation: -g-6, 9d+3, -12y+20, 14n-29, -2c, x+21/2

3 0
2 years ago
Read 2 more answers
Which expression is equivalent to StartFraction b Superscript negative 2 Baseline Over a b Superscript negative 3 Baseline EndFr
nignag [31]

Answer:

  • \frac{b^{-2}}{ab^{-3}}=\frac{b}{a}

Step-by-step explanation:

Writing the description in algebraic translation

\frac{b^{-2}}{ab^{-3}}

so we have to find the expression which will be equal to \frac{b^{-2}}{ab^{-3}}.

Considering the expression

\frac{b^{-2}}{ab^{-3}}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}

so the expression becomes

=\frac{b^{-2-\left(-3\right)}}{a}            ∵ \frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}

\mathrm{Subtract\:the\:numbers:}\:-2-\left(-3\right)=1

=\frac{b}{a}

Therefore,

                    \frac{b^{-2}}{ab^{-3}}=\frac{b}{a}

7 0
3 years ago
Read 2 more answers
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