In the word "boogaboo", there are eight (8) letters while there are only four distinct letters. The number of distinct ordered arrangements can be calculated through the equation,
n = 8!/(2!)(4!)
where there are 2 letter b's and 4 letter o's. The answer to this item is 840.
Answer: 840
Answer: y = 10x + 30 is the correct answer
5p+20=56 you would then subtract the 20 from 56 and then divide the 36 by 5
Since RS bisects PQ at point R, then R is the midpoint of PQ.
PQ = 14 <em>given</em>
PR = RQ <em>definition of midpoint</em>
PR + RQ = PQ <em>segment addition postulate</em>
RQ + RQ = PQ <em>substituted PR with RQ</em>
2RQ = PQ <em> simplified (added like terms)</em>
2RQ = 14 <em> substituted PQ with 14</em>
RQ = 7 <em>divided both sides by 2</em>
Answer: 7 cm
J/-2+7 = -12
j/5 = -12
j/5 • 5 = -12 • 5
j = -60
