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Lerok [7]
2 years ago
13

HELP NEEDED NOW...THIS IS DUE IN 34 MINUTES ...NO LINKS AND NO TROLLING

Mathematics
1 answer:
Hunter-Best [27]2 years ago
6 0

Answer:8. h(t) = -6 ((t-6) -3.7)^2 + 82.14 +20

9.b) At about 7.4 seconds.

Step-by-step explanation

Yes, on #7 the function is located 3 places to the right and 2.5 up, but that's just counting the tiny squares. If you look at the number and problem, on #8, you can't add +2.5, because the rocket wasn't on a platform 2.5 feet high. Remember that outside the parentheses + means up and - means down. So add + 20(ft).    but for question 8, and 9. b), try these answers. please mark brainlest

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5 0
3 years ago
What is the answer to this math problem -5+-3+2
Anit [1.1K]

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Step-by-step explanation:

8 0
2 years ago
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If 1m = 3.3 ft, how many cubic feet is the Kuroshio Sea tank? Volume is 9,450. Show your calculations!
Naddika [18.5K]

Answer:

339604.65 cubic feet

Step-by-step explanation:

We are given that 1 m is equal to 3.3 ft.

1 m = 3.3 ft

This means that if we find the volume of a cube of 1 m, we have its volume as:

1^3 = 1 m^3

In the same way, the volume of a cube of 3.3 ft (1 m) is:

3.3^3 = 35.937 ft^3

This means that:

1m^3 = 35.937 ft^3

The Kuroshio sea tank has volume of 9450 m^3. Its volume in cubic feet is therefore:

1m^3 = 35.937 ft^3\\\\9450 m^3 = 9450 * 35.937 = 339604.65 ft^3

The volume of the tank is 339604.65 cubic feet.

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18y^8x^4w^6 and 30y^7w^3
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Step-by-step explanation:

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