1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
3 years ago
10

Consider the inequality-5(x+7)<-10. write an inequality representing the solution for x

Mathematics
1 answer:
storchak [24]3 years ago
8 0
-5x - 35 = 0
-5x = 0 + 35
-5x/-5 = 35/-5
X = -7
You might be interested in
Which expression shows you how you can use mental math to simplify the expression (53 + 23) + 7 most easily? A. 7 + (23 + 53) B.
Ymorist [56]

Answer:

C. 53 + (23 + 7)

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
There are 24 boys and 16 girls in a hall, each holding coins in their hand.
Dmitry_Shevchenko [17]

Answer:

27

Step-by-step explanation:

total=average ×no.

18×40=720 the no. of coins for all children

12×24=288 no. of coins for boys

720-288=432 for all girls

one girl, mean,divide 432 by 16= 27

5 0
3 years ago
An athlete plans to run 3 miles. each lap around the school yard is 3/7 mile. how many laps will the athlete run?
Maksim231197 [3]
He will need to run 7 laps.
8 0
3 years ago
Hey Bestie! 50 pts Pls help! Real answers only pls &lt;3
frosja888 [35]

Answer:

1. \: 3i

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

\sqrt{ - 1(9)}

\sqrt{ - 1}  \times  \sqrt{  9}

i \times  \sqrt{9}

i \times  \sqrt{ {3}^{2} }

i \times 3

3i

<h2>2. \:  \sqrt{ - 8}</h2>

\sqrt{ - 1(8)}

\sqrt{ - 1}  \times  \sqrt{8}

i \times  \sqrt{8}

i \times  \sqrt{ {2}^{2} \times 2 }

2i \sqrt{2}

<h2>3. \:  \sqrt{ - 80}</h2>

\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

5i \sqrt{3}

<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

i \times  \sqrt{72}

i \times ( {6}^{2}  \times 2)

6i \sqrt{2}

<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

i \times  \sqrt{20}

i \times  \sqrt{ {2}^{2}  \times 5}

2i \sqrt{5}

<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

i \times  \sqrt{27}

i \times  \sqrt{ {3}^{2}  \times 3}

3i \sqrt{3}

<h2>8. \:  \sqrt{ - 12}</h2>

\sqrt{ - 1 \times 12}

i \times  \sqrt{12}

i \times  \sqrt{4(3)}

2i \sqrt{3}

<h2>9. \:  \sqrt{ - 125}</h2>

\sqrt{ - 1}  \times  \sqrt{125}

i \times  \sqrt{ {5}^{2} \times 5 }

5i \sqrt{5}

<h2>10. \:  \sqrt{ - 180}</h2>

\sqrt{ - 1}  \times  \sqrt{180}

i \times  \sqrt{ {6}^{2} \times 5 }

6i \sqrt{5}

<h3>Hope it is helpful...</h3>
5 0
3 years ago
Use synthetic division to solve (2x^3+4x^2-35x+15) divided by (x-3) What is the quotient?
Salsk061 [2.6K]

Answer:


Step-by-step explanation:

The only thing you need to watch carefully is the divisor which in this case is   x - 3. The divisor, in synthetic division, is the number that will make the binomial go to 0.  

x - 3 =0

x = 3

So the divisor is 3.

3  ||  2    4    -35    15

             6     30    -15

======================

       2   10    -5      0

So the quotient is

2x^2 + 10x - 5 with no remainder


7 0
3 years ago
Read 2 more answers
Other questions:
  • Math help ...............,,,.,
    14·1 answer
  • Factorise them please
    7·2 answers
  • What is the square root of 444
    5·2 answers
  • A(n)=3/2(-2)^(n-1). What is the 3rd term in the sequence?
    11·2 answers
  • Find the greatest common factor for the group of numbers. 12 ​, 28 ​, 24
    15·1 answer
  • Sum 2 5/8 + 4 1/8 = ?
    12·2 answers
  • What the answer for 3(X+5)=27
    8·2 answers
  • 100 point NO SAMPLE ANSWERS PLEASE!
    11·2 answers
  • Please need help fast thank you. The problem is in the picture.
    8·2 answers
  • Does anyone know how to answer this
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!