•divide both sides by 3
•take the square root of both sides
•subtract 2 from both sides
(used the Khan academy hints so this is 100% correct)
Answer:
total distance = 3300 ft
Step-by-step explanation:
we know here displacement S is in vector form that is
......................1
![\vec{S} = (3\hat{i}+6\hat{j}) + (-7\hat{i}-3\hat{j})](https://tex.z-dn.net/?f=%5Cvec%7BS%7D%20%3D%20%283%5Chat%7Bi%7D%2B6%5Chat%7Bj%7D%29%20%2B%20%28-7%5Chat%7Bi%7D-3%5Chat%7Bj%7D%29)
and
![\vec{S} =(-4\hat{i}+3\hat{j})](https://tex.z-dn.net/?f=%5Cvec%7BS%7D%20%3D%28-4%5Chat%7Bi%7D%2B3%5Chat%7Bj%7D%29)
and
magnitude is
![\left| \vec{S} \right| = \sqrt{(-4)^2+3^2}](https://tex.z-dn.net/?f=%5Cleft%7C%20%5Cvec%7BS%7D%20%5Cright%7C%20%3D%20%5Csqrt%7B%28-4%29%5E2%2B3%5E2%7D)
![\left| \vec{S} \right| = \sqrt{25}](https://tex.z-dn.net/?f=%5Cleft%7C%20%5Cvec%7BS%7D%20%5Cright%7C%20%3D%20%5Csqrt%7B25%7D)
![\left| \vec{S} \right| = 5](https://tex.z-dn.net/?f=%5Cleft%7C%20%5Cvec%7BS%7D%20%5Cright%7C%20%3D%205)
so here distance from home to cafe is
S = 5 × 660
total distance = 3300 ft
A) Possible outcomes are ...
(1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)
for a total of 7 out of 36 outcomes that match your requirements.
p(3 < sum ≤ 5) = 7/36
B) Possible outcomes are ...
(6, 1), (6, 3), (6, 5), (1, 6), (3, 6), (5, 6)
for a total of 6 out of 36 outcomes that match your requirements.
p(6 and odd) = 6/36 = 1/6
Answer:
y=2x+8
Step-by-step explanation:
Alright so, to find the equation, we need to find the slope first. We can do that by turning the input and output into coordinates.
(1,10) and (2,12)
To find the slope, we do:
![\frac{12 - 10}{2 - 1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%20-%2010%7D%7B2%20-%201%7D%20)
Which equals to 2
So right now we can say that the equation is:
y=2x+b
In order to find b, the constant, we just need to plug in the y values and x value of a coordinate:
10=2(1)+b
10=2+b
8=b
So now we can say that the equation is:
y=2x+8