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3 years ago

Geometry please help

Mathematics

1 answer:

ella [17]3 years ago

5 0

Answer:

1. A sound wave in air has a frequency of 262 Hz and travels at a speed of 330 m/s.

2. Sound has a speed of 340 m/s in air at room temperature.

3. A wave has a frequency of 500 Hz and a wavelength of

4. The speed of light is 3.0x10^8 m/s, calculate for the frequency.

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PLEASE HELP!! It’s due today and i don’t know how to do it.

lara [203]

Answer:

Step-by-step explanation:

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2 years ago

For what value of p would the statement 5p = 30 be true?<br>

shtirl [24]

Answer:

Step-by-step explanation:

divide both sides of the equals by 5 to get p on its own

5p divided by 5 = p

30 divided by 5 = 6

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3 years ago

The following function represents the production cost f(x), in dollars, for x number of units produced by company 1:

solniwko [45]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,

mafiozo [28]

9514 1404 393

Answer:

maximum: 15∛5 ≈ 25.6496392002
minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

$f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)$

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0

3 years ago

How to solve this problem?

SOVA2 [1]

Covert to a common denominator to help:
A LCD is 24.
12/24, 20/24, and 15/24

So 12/24, 15/24, 20/24
Convert back into their original denominators:
1/2, 5/8, 5/6.
F.

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3 years ago