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The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
For Addison h=85(1/3)
Subtracting both distances we get
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
Step-by-step explanation:
Apply Quoteint of Powers. Divide the intergers. serpately.
Note that Quotient of Powers is
So the answer is
The answer is
or
Answer:
f(x) is continuous on the interval [0, 1], f(0) = <u>-2</u> , and f(1) = <u>1.718</u> . Since f(0) < 0 < f(1) , there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation ex = 3 − 2x, in the interval (0, 1)
Step-by-step explanation:
From the question we are told that
The equation is
The interval is [0, 1]
Generally f(0) is
=>
=>
Generally f(1) is
From the value we see that at x = 0 , f(0) = -2 which is below the x-axis
and the at x = 1 , f(1) = 1.718 which is above the x-axis
Now the according to Intermediate Value Theorem , given the condition stated above, there will exist a root c in the interval such that
f(c) = 0