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2 years ago

Use f(x)=-2x+5 to find x when f(x)=11

1 answer:

3 0

When it asks this question, ultimately you want to plug 11 into x because its f(x). 11=-2+5.

Then you subtract 5 on both sides because of the opposite of addition is subtraction.

6=-2x

now divide on both sides

x=-3

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Ryder Industries is considering a project that will produce cash inflows of $92,000 a year for five years. What is the internal

RSB [31]

Answer:

20.02%

Step-by-step explanation:

Formula : $NVP = 0 =-P_0 + \frac{P_1}{(1+IRR)} + \frac{P_2}{(1+IRR)^2} + . . . +\frac{P_n}{(1+IRR)^n}$

$P_0 = 275000$

n = 1,2,3,4,5

Substitute the values in the formula :

$0 =-275000 + \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}$

$275000 = \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}$

Solving for IRR using calculator

IRR = 20.02

Hence the internal rate of return if the initial cost of the project is $275,000 is 20.02%

4 0

3 years ago

Examine the linear equation. 8x – y = –6 Choose the slope-intercept form of the equivalent equation:

alexdok [17]

Step-by-step explanation:

The slope-intercept form can be obtained by solving for y.

8x-y=-6

-8x

-y=-8x-6

divide by negative 1 to turn y positive.

y=8x+6

6 0

3 years ago

Read 3 more answers

Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))

Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

$\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5$

Use properties:

$\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA$

Thus,

$\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11$

3 0

3 years ago

Evacuate the following using suitable identities (102)^3

snow_lady [41]

The value of $(102)^3$ exists 1061208.

<h3>How to estimate the value of $(102)^3$ ?</h3>

Let us rewrite $(102)^3$ as $(100+2)^3$

Now utilizing the identity $(a+b)^3=a^3+b^3+3ab(a+b)$ , we get

a = 100 and b = 2 then substitute the values of a and b then

$(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]$

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, $(102)^3=1061208$

Therefore, the value of $(102)^3$ exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

#SPJ9

5 0

2 years ago

HELP!! Algebra help!! Will give stars thank u so much <333

Anna35 [415]

Answers:

Part a) $\bf{\sqrt{x^2+(x^2-3)^2}$
Part b) 3
Part c) 2.24
Part d) 1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

$d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\$

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying $d = \sqrt{x^2 + (x^2-3)^2}$ is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\$

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\$

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0

2 years ago