E+r=
(e=9)
r=1.50)
or 9+1.50=
I think
The answer:
<span>the average rate of change for the first 50 seconds:
it is v= 100 m/ 50 s = 2 m/s
</span><span>Thomas speed is 2 m in each second for the first 50 seconds.
</span><span>The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s
</span>
Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
The second choice
7+ -13= -6
