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Deffense [45]
3 years ago
11

What is the value of f(-2) for the given function

Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0

Copy down the given function:

f(x)=3•2^x

Now replace both instances of x with -2:

f(-2) = 3*2^(-2).                                1

Recall that 2^(-2) is the same as ------ = 1/4

                                                      2^2

Therefore, f(-2) = 3*2^(-2) = 3*(1/4) = 3/4

Remember that exponentiation has to be carried out before multiplication.  That's why I did 2^(-2) before multiplying by 3.

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Plz i need help and plz explain
Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

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(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

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