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schepotkina [342]
3 years ago
15

Please help! And please explain how you did it!

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

<

Explanation:

turn 5/11 into a decimal: 0.45 which is LESS than 0.50 (0.5).

Ipatiy [6.2K]3 years ago
5 0

Answer:

<

Step-by-step explanation:

When comparing fractions and decimals/fractions and percentages/decimals and percentages, it's always good to convert them to have the same type on either side. However, you don't really need to with this problem.

Here's a trick: the larger the denominator is in a fraction, the smaller the value of the fraction is. If the fraction on the left were 5/10, then we know that it would be equal to 0.5 (you can convert either one). Now, since the denominator of the fraction is one <em>greater than</em> 10, we know that the fraction's value is just a little bit <em>less than</em> 5/10. This makes the fraction less than 0.5.

I hope it made sense. Brainliest would be cool but no worries.

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In his free time, Gary spends 11 hours per week on the Internet and 11 hours per week playing video games. If Gary has five hour
Tpy6a [65]

Answer:

62.8% OR 0.628

Step-by-step explanation:

11 hours playing video games

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0.628 into a fraction is 62.8%

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3 years ago
In triangle ABC, if sin A= 4/5 and tan A= 4/3, the what is cos A? 3/5 4/5 3/4 5/3
laila [671]

Answer:

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Step-by-step explanation:

3 0
3 years ago
F(x)
mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if \lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x). This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty

\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}

g(x) = \frac{1}{x + 1}

The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0
2 years ago
The volume of a cone of radius r and height h is V=1/3πr^2 h.Solve for r.Please help me anyone!!!! I need to know the answer now
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r =   \sqrt{\dfrac{3V}{ \pi h}}
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