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kkurt [141]
3 years ago
7

Marilu invested $3,000 in a fund with an interest rate of 2.5% compounded semi-

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

$ 3,396.81

Step-by-step explanation:

The formula uses to calculate the amount of an investment after t years which is compounded is given as:

A = P(1 + r/n)^nt

Where:

A = Amount of Investment after t years

P = Principal = $3,000

r = Interest rate = 2.5 %

t = Number of years of Investment = 5 years

n = Compounding frequency = semi annually = 2

First, convert R percent to r a decimal

r = R/100

r = 2.5%/100

r = 0.025 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 3,000.00(1 + 0.0125/2)^(2×5)

A = $ 3,396.81

The total Investment from compound interest on an original principal of $3,000.00 at a rate of 2.5% per year compounded 2 times per year over 5 years is $ 3,396.81.

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3 years ago
z 5 ​ − z+2 2z+4 ​ =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z
yan [13]

Answer:

The sum of all the possible values for z that satisfy the above equation is -5.

Step-by-step explanation:

The given equation is

\frac{5}{z}-\frac{2z+4}{z+2}=-3

We need to find the sum of all the possible values for z that satisfy the above equation.

The given equation can be rewritten as

\frac{5}{z}-\frac{2(z+2)}{z+2}=-3

Cancel out common factors.

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Add 2 on both sides.

\frac{5}{z}-2+2=-3+2

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Multiply both sides by -1.

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3 years ago
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vekshin1

Answer:

-11

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