Work out the balance for £1500 invested for 2 years at 3.7% per annum
1 answer:
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Answer:
Step-by-step explanation:
The sample space is shown in the attached photo.
Probability = number of favourable outcomes/total number of outcomes.
Looking at the diagram, the total possible outcomes is 36.
A) from the diagram, the total number of events in which the sum of the numbers is odd is 18. Therefore, the probability that the sum of the numbers is odd is
18/36 = 1/2
B) the total number of events in which the sum of the numbers is 10 or more is 6. Therefore, the probability that the sum of the numbers is 10 or more is
6/36 = 1/6
C) the total number of events in which 3 appears on each of the two dice is 1. Therefore, the probability that 3 appears on each of the two dice is
1/36
Answer:
The length of the wire is 15 ft.
Step-by-step explanation:
The solution of this exercise comes from an application of the Pythagorean theorem. The explanation here is complemented with the figure attached.
In the figure the segments AB and CD represents the vertical poles, where the length of AB is 6 ft and the length of CD is 15 ft. We want to find the length of the segment BD, that represents the stretched wire. The length of the segment AC is 12 ft, which is the distance between the poles.
If we draw an imaginary line from A perpendicular to DC, we obtain a rectangle ABEC, and a right triangle BED. Then, the length of BE is 12 ft. Moreover, the length of CE is 6 ft, because is equal to the length of AB. Hence, the length of DE is 9 ft, because DE = DC-EC.
As we want to find the length of the hypotenuse BD of the right triangle BED, and we already have the lengths of the other two sides, we only need to apply the Pythagorean theorem. This is
Then, taking square roots in both sides: BD=15 ft.
