It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (2
4)=8 - The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
Answer:
12.
Step-by-step explanation:
160000000 =
move the decimal so only one number is to the left
we need to move it 8 times
1.60000000 *10^8
1.6*10^8
58413000000
move the decimal so only one number is to the left
5.8413000000 * 10^10
5.8413*10^10
Answer:
50%
Step-by-step explanation:
17/34 = .50
I think it’s linear. no numbers repeat. i could be wrong but LOL