Answer:
-5
Step-by-step explanation:
-2x+7>17
-2x>17-7
-2x>10
Divide both sides by -2
-2x<10
-2 -2
x<-5
Note:when dividing with a negative the signs changes
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
280
Step-by-step explanation:
V=Bh
V=1/2(7x10)8 *it is a triangluar pyrmid so the base is a triangle*
V=1/2x70x8
V=35x8
V=280
Answer:280
3/4 and 6/8 are equal and this is right I believe