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tiny-mole [99]
3 years ago
10

What is the direct variation of y=8x

Mathematics
1 answer:
Digiron [165]3 years ago
8 0
y = 8x =\ \textgreater \   \frac{y}{x} = 8
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Which of the following is the solution set to the equation: 2x(x-3)(4x+1)=0?
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Answer:

(1) {-1/4, 0, 3}

Step-by-step explanation:

Step 1: Factor left side of equation.

2x(4x+1)(x−3)=0

Step 2: Set factors equal to 0.

2x=0 or 4x+1=0 or x−3=0

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kvv77 [185]

Answer:

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Step-by-step explanation:

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MrRa [10]

For this case we have the following expression:

(8a^{-3})^{-\frac{2}{3}}

For power properties we have:

(8^{-\frac{2}{3}} a^{-3*-\frac{2}{3}})

Rewriting the exponents of the expression we have:

(8^{-\frac{2}{3}} a^{3*\frac{2}{3}})

(8^{-\frac{2}{3}} a^2)

(\frac{1}{8^{\frac{2}{3}}} a^2)

Using the cubic root we have:

(\frac{1}{\sqrt[3]{8^2}} a^2)

(\frac{1}{\sqrt[3]{64}} a^2)

(\frac{1}{\sqrt[3]{4^3}} a^2)

Simplifying the expression we have:

(\frac{1}{4} a^2)

Answer:

The equivalent expression is given by:

(\frac{1}{4} a^2)

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Tju [1.3M]
Well just show each par of the expression like you would show them 13+5 and then x 2 then -6 and +8. Just show each part of the expression
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3 years ago
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