(x+4)(x-3)=30
x^2 +x -12 =30
x^2 +x =42
x^2 +x -42 =0
(i solved it by factorising: _x^2 × -42)
x^2 -6x +7x -42 =0
x(x-6) +7(x-6) 0
(x-6)(x+7)=0
x=6; x=-7
since it's a length, x can't be a negative number, so it must be 6
Answer:
3(-1)-5-6(-1)-2. You found the value of X, so you need to put it back into the equation to see if it equals out.
Answer:
33°
Step-by-step explanation:
Where a transversal crosses parallel lines at right angles, all of the angles at their points of intersection are right angles.
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Angles at U are right angles, congruent to ∠UXZ. So, acute angle UXW in right triangle UXW is the complement of acute angle UWX:
∠UXW = 90° -57° = 33°
The students = 18/1 x 12
the students = 18 x 12
the students = 216
There are 216 students attending the school
