Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
Answer:

Step-by-step explanation:
Given



Required
Determine the final price
If all discounts are taken, the final price is:

This gives:


No, reflections do not chage shape, size or area. The only transformation that does that is dilation.

when does it hit the ground? check the picture below.

at that moment, the velocity is -32(3).