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ELEN [110]
3 years ago
10

How do you solve this?

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0

Let's solve your equation step-by-step.


−7x=−2x2+15


Step 1: Subtract -2x^2+15 from both sides.


−7x−(−2x2+15)=−2x2+15−(−2x2+15)


2x2−7x−15=0


Step 2: Factor left side of equation.


(2x+3)(x−5)=0


Step 3: Set factors equal to 0.


2x+3=0 or x−5=0


x=  \frac{-3}{2} or x=5

Answer:


x=    \frac{-3}{2} or x=5


Hope this helps

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185g in the ratio 2:3
beks73 [17]

ratio 2:3

2 + 3 = 5

185 / 5 = 37

so

37 x 2 = 74

37 x 3 = 111


Answer

185 g in the ratio 2:3 = 74: 111

8 0
3 years ago
Ricky ate 2 soft tacos, and 4 of his friends ate s soft tacos. If there were 18 2 points
shtirl [24]

Answer:

Each friend ate 4 tacos.

Step-by-step explanation:

"4 of his friends ate s tacos" is unclear. I assume it should be

"4 of his friends ate s tacos each."

total tacos = 2 + 4s = 18

4s = 16

s = 4

His four friends ate a total of 16 tacos, each friend eating 4 tacos.

Ricky's reason, i.e., that 6s = 18, is incorrect.

6s = 4s+2s, where 4s is what his friends ate in total.

That implies that Ricky ate 2s tacos, instead of 2 tacos. If 2s = 2 then s = 1, but then 6s ≠ 18.

4 0
3 years ago
5cm<br> 2cm<br> 8cm<br> Volume of 3D shape
11Alexandr11 [23.1K]

Answer:

80 cm^3 (cm cubed)

Step-by-step explanation:

5 x 2 x 8

4 0
3 years ago
Help please anyone:)
Anna007 [38]
The answer is -0.75.
7 0
3 years ago
Read 2 more answers
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0
3 years ago
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