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3 years ago

What is the equation

Mathematics

1 answer:

IRINA_888 [86]3 years ago

7 0

Answer:

1+1= 11

1Step-by-step explanation:

I might be wrong so if i am right pls give me a thanks

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Is square root of 7 a rational number

MAVERICK [17]

Answer: Yeah its a rational number.

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2 years ago

What two numbers have a product of -25 and a sum of 24?

NemiM [27]

-1 and 25

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3 years ago

What is the total area of this composite figure rounded to the nearest hundredth?

weqwewe [10]

Answer:

choice #4, total=31.14 mm^2

Step-by-step explanation:

14x2=28 is area of rectangle

1^2xPi=area of small circle

3.14=area of small circle

total=31.14 mm^2

7 0

3 years ago

Find the taylor polynomial t3(x) for the function f centered at the number

inysia [295]

Answer:

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

Step-by-step explanation:

We are given that

$f(x)=7tan^{-1}(x)$

a=1

$T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}$

Substitute n=3 and a=1

$t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}$

$f(x)=7tan^{-1}(x)$

$f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}$

Where $tan^{-1}(1)=\frac{\pi}{4}$

$f'(x)=\frac{7}{1+x^2}$

Using the formula

$\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}$

$f'(1)=\frac{7}{2}$

$f''(x)=\frac{-14x}{(1+x^2)^2}$

$f''(1)=-\frac{7}{2}$

$f''(x)=-14x(x^2+1)^{-2}$

$f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})$

By using the formula

$(uv)'=u'v+v'u$

$f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}$

$f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}$

$f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}$

Substitute the values

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3$

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

7 0

3 years ago

Find the value of x. Round to the nearest tenth. Please Help Me!!!

levacccp [35]

Answer:

x ≈ 4.1 cm

Step-by-step explanation:

The segment from the centre to the chord is a perpendicular bisector

The third side of the triangle = 14.6 ÷ 2 = 7.8

We now have a right triangle with legs x and 7.8 with hypotenuse 8.8

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 7.8² = 8.8²

x² + 60.84 = 77.44 ( subtract 60.84 from both sides )

x² = 16.6 ( take the square root of both sides )

x = $\sqrt{16.6}$ ≈ 4.1 ( nearest tenth )

3 0

2 years ago

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