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Law Incorporation [45]
2 years ago
5

Find the slope of the line​

Mathematics
2 answers:
PolarNik [594]2 years ago
8 0

Answer:

no

Step-by-step explanation:

ask a teacher so people might lie abt the answer

Mama L [17]2 years ago
3 0

Answer:

- 5/3

Step-by-step explanation:

This slope would be a positive slope since we have the dot on the negative side but it looks like it's in the ones but it's negative 5/3 in my opinion good luck

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Find the area of the shaded region. Round your answer to the nearest hundredth.
Anit [1.1K]
The 4 curved white corners = 1/4 of whole circle with radius 1/2×6
total white area = 4 [1/4 (pi)(3)^2] = 9pi = 28.27

So the shaded green region (S) = total square - total white area

S = 6×6 - 28.27 = 36 - 28.27 = 7.73 sq. m
5 0
3 years ago
Use the distributive property to simplify the expression.
zepelin [54]

Option D

Using the distributive property, -7(8x – 3) + x = -55x + 21

<em><u>Solution:</u></em>

Given that we have to use distributive property to simplify the given expression

Given expression is:

-7(8x – 3) + x

Let us first understand about distributive property

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

<em><u>The distributive property is represented as:</u></em>

a(b + c) = ab + ac

Apply this property in given expression for -7(8x - 3)

-7(8x - 3) = (- 7 \times 8x) + (-7 \times -3)\\\\-7(8x - 3) = -56x +21

Apply the above result in given expression

-7(8x - 3) + x = -56x + 21 + x

Combine the like terms. Add -56x and x

-7(8x - 3) + x = -56x + 21 + x = -55x + 21\\\\-7(8x - 3) + x = -55x + 21

Thus the given expression is simplified. Option D is correct

6 0
2 years ago
How do you find how many cups are in a gallon
Lisa [10]
First we need to find the volume of water that can be filled in water 
   Then we will use the equation that
                  1 gallon = 3.8 lires
Then by using this we will calculate the amount of cup used by equalizing with litres and then by gallons and then calculate number of cups in gallons

8 0
3 years ago
Read 2 more answers
A principal of ​$6000 is invested in an account paying an annual rate of 5​%. Find the amount in the account after 4 years if th
astra-53 [7]

Solution :

Given :

Principal amount deposited, P = $ 6000

Rate of interest, r = 5%

Number of years, t = 4 years

When the deposited amount is compounded semiannually, i.e. n = 2

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{2}\right)^{2 \times 4}$

$FV = 6000 \times (1.025)^8$

       = 6000 x 1.2184

        = 7310.4

Therefore, after 4 years there will be $ 7310.4 in the amount when compounded semi annually.

When the deposited amount is compounded quarterly, i.e. n = 4

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{4}\right)^{4 \times 4}$

$FV = 6000 \times (1.0125)^{16}$

       = 6000 x 1.219889

        = 7319.334

Therefore, after 4 years there will be $ 7319.334 in the amount when compounded quarterly.

When the deposited amount is compounded monthly, i.e. n = 12

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{12}\right)^{12 \times 4}$

$FV = 6000 \times (1.0041667)^{48}$

       = 6000 x 1.22089

        = 7325.34

Therefore, after 4 years there will be $ 7325.34 in the amount when compounded monthly.

8 0
3 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
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