v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
I would help you but I don’t know
Step-by-step explanation:
Answer:
y = x-2
Step-by-step explanation:
y = mx + b as an equation
m = slope
slope = (change in y) / (change in x) = (y₂-y₁)/(x₂-x₁) = (y₁-y₂)/(x₁-x₂) = (2-(-2))/(4-0) = 4/4 = 1
y = 1*x + b
plug a value in, e.g. (0, -2)
-2 = 1 * 0 + b
-2 = b
our equation is thus
y = x - 2
Answer:
B. 0.83
Step-by-step explanation:
I calculated it logically
