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olga_2 [115]
3 years ago
14

Pls help timed test I don’t know how to do this and yeah

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0
It’s A 26.7 hope this helps!!!!
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If f(x) = 2x^2+1 and g(x) =x^2-7 find (f+g)(x)
sp2606 [1]

Answer:f=−

​7

​

​x

​2

​​ +1−2g−x

​​  

Step-by-step explanation:

1 Subtract {x}^{2}x

​2

​​  from both sides.

2{x}^{2}+1-g-x-{x}^{2}=-7f+g2x

​2

​​ +1−g−x−x

​2

​​ =−7f+g

2 Simplify  2{x}^{2}+1-g-x-{x}^{2}2x

​2

​​ +1−g−x−x

​2

​​   to  {x}^{2}+1-g-xx

​2

​​ +1−g−x.

{x}^{2}+1-g-x=-7f+gx

​2

​​ +1−g−x=−7f+g

3 Subtract gg from both sides.

{x}^{2}+1-g-x-g=-7fx

​2

​​ +1−g−x−g=−7f

4 Simplify  {x}^{2}+1-g-x-gx

​2

​​ +1−g−x−g  to  {x}^{2}+1-2g-xx

​2

​​ +1−2g−x.

{x}^{2}+1-2g-x=-7fx

​2

​​ +1−2g−x=−7f

5 Divide both sides by -7−7.

-\frac{{x}^{2}+1-2g-x}{7}=f−

​7

​

​x

​2

​​ +1−2g−x

​​ =f

6 Switch sides.

f=-\frac{{x}^{2}+1-2g-x}{7}f=−

​7

​

​x

​2

​​ +1−2g−x

​​  

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