Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
16/9 because (3/4)^-2 simplified is 16/9
Equation 1) 4x + 2y = 8
Equation 2) 16x - y = 14
Multiply all of equation 2 by 2.
2) 2(16x - y = 14)
2) 32x - 2y = 28
1) 4x + 2y = 8
Add equations together.
36x = 36
Divide both sides by 36.
x = 1
Plug in 1 for x in the first equation.
4x + 2y = 8
4(1) + 2y = 8
4 + 2y = 8
Subtract 4 from both sides.
2y = 8 - 4
2y = 4
Divide both sides by 2.
y = 4/2
y = 2
So, x = 1, y = 2
~Hope I helped!~
Line Segment AB<span> ≅ Line Segment DB </span>
Answer:
Step-by-step explanation:
- cotx cos x - cot x = 0
- cotx( cosx - 1) = 0
1. <u>cotx = 0</u>
- x = π/2 + πn
- In the interval [0, 2π] we have π/2 and 3π/2
2. <u>cosx = 1</u>
- x = 0 + 2πn
- In the given interval we have 0 and 2π
<u>So the solution set is:</u>
