Can u help me with this and show work i only have 20 min and theres more

Write the Egyptian numeral as a Hindu-Arabic numeral

Katyanochek1 [597]

Answer:

2635

Step-by-step explanation:

the first two stand for 1000

so

2000

is the first part

the second numeral stands for 100

there are 6 of them

so

600

is the second part

the third numeral stands for 10 and there are 3 of them

thus

30

is the third part

there are 5 lines so the last part is 5

so your answer is 2635

5 0

1 year ago

Brendon sells tires at the local auto parts store. He told a customer that the tire width for a new tire was 21.5 centimeters. W

miss Akunina [59]

Answer:

Choice D

Step-by-step explanation:

When you convert a unit to a smaller unit it will always get bigger so in this case you will move the decimal point to the right so 21.5 will become 215.

8 0

2 years ago

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Please Help....................................

Olegator [25]

The juice drink that is the most popular with customers is Lemon Lift

8 0

3 years ago

What is numerical coefficient of this term -3z

9966 [12]

Answer: -3

The coefficient is the number that is getting multiplied by the variable

5 0

3 years ago

Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of

GenaCL600 [577]

Close off the hemisphere $S$ by attaching to it the disk $D$ of radius 3 centered at the origin in the plane $z=0$ . By the divergence theorem, we have

$\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV$

where $R$ is the interior of the joined surfaces $S\cup D$ .

Compute the divergence of $\vec F$ :

$\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2$

Compute the integral of the divergence over $R$ . Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

$\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}$

So the volume integral is

$\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5$