Answer:
B and E
Step-by-step explanation:
In the function f(m)= -50m+300
-50 is the gradient meaning it is the rate of change per month. This means that the rate of change is -50 since this is the coefficient of m.
Also, -50m must be negative since m represents a month and you cant have negative months, so you know that the amount of money is decreasing
Answer:
- 6 bunches of bananas
- 7 pounds of apples
Step-by-step explanation:
We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.
Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...
6B +8(13 -B) = 92
-2B + 104 = 92 . . . . . eliminate parentheses
B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B
13-B = 7 . . . . . . . . . . . the number of pounds of apples
The customer bought 6 bunches of bananas and 7 pounds of apples.
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<em>Comment on the solution</em>
You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.
Answer:
a) (0, ∞)
b) (-∞, ∞)
c) x = 0
Step-by-step explanation:
It helps to have some idea what the log function is.
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a) The domain is all positive numbers: (0, ∞).
b) The range is all real numbers: (-∞, ∞). (The vertical translation downward by 5 units does not change that.)
c) There is a vertical asymptote where the argument of the log function is zero: at x=0.
For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
So lets do it like this:
z = (X-Mean)/SD
<span>z1 = (8-12)/2 = - 2 </span>
<span>z2 = (16-12)/2 = + 2 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean more or less 2SD covers 95% of the values </span>
So t<span>he percentage of data points falling between 8 and 16 = 95%
</span>I hope this can help
