The given polynomial function has 1 relative minimum and 1 relative maximum.
<h3>What are the relative minimum and relative maximum?</h3>
- The relative minimum is the point on the graph where the y-coordinate has the minimum value.
- The relative maximum is the point on the graph where the y-coordinate has the maximum value.
- To determine the maximum and the minimum values of a function, the given function is derivated(since the maximum or minimum is obtained at slope = 0)
<h3>Calculation:</h3>
The given function is
f(x) = 2x³ - 2x² + 1
derivating the above function,
f'(x) = 6x² - 4x
At slope = 0, f'(x) = 0 (for maximum and minimum values)
⇒ 6x² - 4x = 0
⇒ 2x(3x - 2) = 0
2x = 0 or 3x - 2 = 0
∴ x = 0 or x = 2/3
Then the y-coordinates are calculated by substituting these x values in the given function,
when x = 0;
f(0) = 2(0)³ - 2(0)² + 1 = 1
So, the point is (0, 1)
when x = 2/3;
f(2/3) = 2(2/3)³ - 2(2/3)² + 1 = 19/27
So, the point is (2/3, 19/27)
Since y = 1 is the largest value, the point (0, 1) is the relative maximum for the given function.
So, y = 19/27 is the smallest value, the point (2/3, 19/27) is the relative minimum for the given function.
Thus, option A is correct.
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The answer to that is - 10
Answer:
hope it will help u in understanding
Answer:
the answer is 1/3
Step-by-step explanation:
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Step-by-step explanation:
This is a probability related problem.
Probability is the likelihood of an event to occur;
Pr = 
The sample space here is from 1 to 25 which is 25
A.
Pr of a card marked 8; we have just 1 possible outcome;
Pr(8) =
B.
Pr of drawing a card that is a multiple of 5;
Multiples of 5 = 5, 10, 15 and 25
Pr (multiples of 5) =
C.
Pr of drawing a card with odd numbers:
Number of odd numbers between 1 and 25 = 13
Pr(odd numbers) =
D.
Pr of drawing a number with square number on it;
Square numbers between 1 and 25 = 1, 4, 9, 16 and 25
Pr(square numbers) =
= 