The answer is median, because the data is skewed and there is an outlier.
There is NO solution.
Cancel t on both sides (1/5 = 7/8).
Since 1/5 = 7/8, that doesn't make any sense so that is inapplicable ( So NO answer).
Answer:
The probability of Javier volunteers for less than three a month is 25%
Step-by-step explanation:
According to the questions,
The probability of Javier to attend exactly 5 events :-
P ( x = 5 ) = 25% = 
The probability of Javier to attend exactly 4 events :-
P ( x = 4 ) = 
The probability of Javier to attend exactly 3 events :-
P ( x = 3 ) = 
The probability of Javier to attend exactly 2 events :-
P ( x = 2 ) = 
The probability of Javier to attend exactly 1 events :-
P ( x = 1 ) = 
The probability of Javier to attend no events :-
P ( x = 0 ) = 
Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).
P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )
P ( x < 3 ) =
=
=
= 0.25 = 25 %.
Answer:
C. is the correct answer
Step-by-step explanation:
A. is incorrect because the sequence does not start with 15
B. is incorrect because the pattern increases by 5, not multiplied by 5
C. is correct because all of the even numbers in the pattern do end in 0
D. is incorrect because even numbers don't end in 5's
Hope this helps!