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Troyanec [42]
3 years ago
15

Who’s done this packet already? Or who’s finished it? MESSAGE ME ASAP! Thanks!!!!

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer:

1. D. 2x + y = 4

2. A

Step-by-step explanation:

Problem 1:

To find the equation in standard form, first find the equation of the graph in slope-intercept form, y = mx + b.

Where, m = slope and b = y-intercept.

Slope (m) = ∆y/∆x

Using two points on the line, (0, 4) and (2, 0):

Slope (m) = (0 - 4)/(2 - 0) = -4/2 = -2

m = -2

y-intercept is the y-coordinate of the point where the line intercepts the y-axis = 4.

Thus,

b = 4

Substitute m = -2, and b = 4 into y = mx + b:

y = -2x + 4

Rewrite in standard form:

2x + y = 4

Problem 2:

The funtion y = ½(x) + 2 is given in the slope-intercept form y = mx + b.

m = slope = ½

b = y-intercept = 2

Therefore, the graph that has a slope value of ½ and y-intercept value of 2 would be the graph that represents the given function.

Thus, the graph in option A, has a y-intercept (b) value of 2 (the line intercepts the y-axis at y = 2).

Also, the slope of graph A = ½.

Therefore, the answer is option A.

You might be interested in
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
4 years ago
Can someone help me with this page?
Roman55 [17]
Sure
i will help with the page if i can do it…

6 0
3 years ago
Read 2 more answers
Can anyone help me please
kicyunya [14]

Answer:

yes wait im doing it. do I put them un order

3 0
3 years ago
-4x-7-3x+4=25<br><img src="https://tex.z-dn.net/?f=what%20is%20-%204x%20-%207%20-%203x%20%2B%204%20%3D%2025%20" id="TexFormula1"
kodGreya [7K]
Hi I don’t really understand can you explain a little bit please
8 0
3 years ago
Does the following represent the Substitution Property? If y = 2x and x = 6 then y = 12.
kati45 [8]

YES because 2 times 6 =12


3 0
3 years ago
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