Question

Which linear function f has the values f(0)=3 and f(−4)=0 f(x)=34x−4 f(x)=34x+3 f(x)=43x−4 f(x)=43x+3

Answer 1

Answer:

$f(x) = \frac{3}{4}x +3$

Step-by-step explanation:

Given

$f(x) = \frac{3}{4}x +3$

$f(x) = \frac{4}{3}x-4$

Required

For which function is $f(0) = 3$ and $f(-4) = 0$ true

$f(x) = \frac{3}{4}x +3$

Substitute 0 for x

$f(0) = \frac{3}{4} * 0 + 3$

$f(0) = 0 + 3$

$f(0) = 3$

Substitute -4 for x

$f(-4) = \frac{3}{4} * -4 + 3$

$f(-4) = -3 + 3$

$f(-4) = 0$

Hence:

$f(x) = \frac{3}{4}x +3$ is true for $f(0) = 3$ and $f(-4) = 0$