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3 years ago

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om was using wire of the following thicknesses .33 mm, .275 mm, .25 mm, and .3 mm for some electrical work. Order the wire from

thickest to thinnest. A. .275, .25, .3, .33 B. .33, .3, .275, .25 C. .3, .33, .25, .275 D. .3, .33, .275, .25

1 answer:

bogdanovich [222]3 years ago

8 0

B. .33 .3 .275 .25 yup, just gotta get over 20 characters

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Kim had 160 cards in a box.She gave 4/10 of the cards to maddy.How many cards did Kim have left in the box

Marysya12 [62]

$\text {Total cards = 160}$

$\text {Cards gave to Maddy = } \dfrac{4}{10} \times 160 = 64
$

$\text {Cards left = } 160 - 64 = 96

$

------------------------------------
Answer: Cards left = 96
------------------------------------

4 0

3 years ago

What is the approximate length of RP? Round to the nearest tenth. 5. 6 units 6. 1 units 8. 3 units 9. 8 units.

kirza4 [7]

The apporoximate length of the RP is 6.1 units, the correct option is B.

<h3>What is Pythagoras theorem?</h3>

The Pythagoras theorem states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of the other two sides of the right-angled triangle.

Given

QR is the tangent to circle P at point Q.

QP = 3 units and QR = 5,.3 units

The length of the RP is given by;

$\rm RP=\sqrt{QP^2+QR^2} \\\\RP=\sqrt{3^2+5.3^2}\\\\ RP=\sqrt{9+28.09} \\\\RP=\sqrt{37.09}\\\\RP= 6.1 \ units$

Hence, the apporoximate length of the RP is 6.1 units.

To know more about Pythagoras theorem click the link given below.

brainly.com/question/11526258

6 0

3 years ago

Help me now pleasee!!!

Mice21 [21]

For this, you have to plot the points on the graph. where it says right hand height, you go down to that number on the x axis (horizontal) and then up to the correct number for right foot length (vertical)

8 0

3 years ago

A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu

Lina20 [59]

Answer:

a) 0.5

b) 0.5

c) 0.67

d) 1

e) 0.83

f) 0.67

Step-by-step explanation:

a)

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

n(S)= Total number of outcome of an experiment=6

P(A)=3/6=1/2=0.5

b)

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

c)

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

d)

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

e)

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

f)

A-C={1,3,5}-{1,3,9,11}={5}

(A-C)∪B={5}∪{7,9,11}={5,7,9,11}

P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0

3 years ago

A manufacturer makes plastic wrap used in food packaging and aims to have a minimum breaking strength of 0.5 kg. If the mean bre

Darina [25.2K]

Answer:

Option D

Step-by-step explanation:

A type I error occurs when you reject the null hypothesis when it is actually true.

The null hypothesis in this case is minimum breaking strength is less than or equal to 0.5.

A type one error would be allowing the production process to continue when the true breaking strength is below specifications.

7 0

3 years ago