<span>The first two terms of a geometric sequence are a1=1/3 and a2=1/6. what is a8 the 8th term?
r=(1/6)/(1/3) = 1/2
a(8)= ar^7 = (1/3)(1/2)^7 = 1/3*1/128= 1/384</span>
Answer:
A
Step-by-step explanation:
we can find using the trigonometric formulas
we can find y by using cosine.
cos = adj / hyp
cos 60 = y / 10
y = 10 cos 60
y = 5
now we can use the Pythagorean theorem since we have the base and hyp
a² + b² = c²
5² + b² = 10²
25 + b² = 100
b² = 75
b = 5√3
I would have to say the answer is=<span>C) 16x3 - 8x2y - 16xy2 - 64y3</span>