(Sin A/ secA) × ( sec A / cos A) = Sin A / cos A = tan A
Question should be cos A ÷ sec A
So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
Answer:
it should be (-8, -7)
Step-by-step explanation:
look up a coordinate plane
Rajid it is (e) 3/4 and please follow me I need a follower
