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Ludmilka [50]
2 years ago
13

AABC ~ AQRS

Mathematics
1 answer:
lyudmila [28]2 years ago
4 0

Answer:

12

Step-by-step explanation:

6/4 is equal to 1.5, multiply that by 8 and you get 12

You might be interested in
Simplify by dividing -5/8 divided by -3/4
aleksandr82 [10.1K]

Answer:

-5/6

Step-by-step explanation:

7 0
3 years ago
A storekeeper has two kinds of flour, one selling for 65 cents per pound, and the other selling for 95 cents per pound. How many
Murrr4er [49]

Answer:

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

Step-by-step explanation:

Let

x ----> amount of 65 cents per pound flour to use

y----> amount of 95 cents per pound flour to use

we know that

x+y=100 ----> y=100-x ----> equation A

0.65x+0.95y=0.83(100) ----> equation B

substitute equation A in equation B

0.65x+0.95(100-x)=0.83(100)

Solve for x

0.65x+95-0.95x=83

0.95-0.65x=95-83

0.30x=12

x=40\ lb

Find the value of y

y=100-40=60\ lb

therefore

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

4 0
3 years ago
Read 2 more answers
Find the area of the trapezoid.
vlabodo [156]

Answer: A.90 cm^2

Step-by-step explanation: A= a+b/2 h

A= 17.5+12.5/2 *6

A = 30/2*6

A= 15*6

A=90

5 0
3 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
For a cube whose side length the lexpression
AleksandrR [38]
Can you give more information?
7 0
2 years ago
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