Answer:
(-3, 2)
Step-by-step explanation:
{3x=7y=5
{5x-2y=-19
solve....
maybe it was 3x + 7y = 5
and 5x - 2y = -19
2*(3x + 7y = 5)
7*(5x - 2y = -19)
-------------
6x + 14y = 10
35x -14y = -133
41x = -123
x = -3
y = ...
5*(-3) - 2y = -19
-15 - 2y = -19
2y = 4
y = 2
(-3, 2)
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Sorry i don't know. i tried. Can you try and help me?
Answer:
the amount he paid is 36.06
Step-by-step explanation:
hope this helps
