Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
<span>A) 3x+4y=17
B) -4x-3y=-18 Multiplying B) by .75
</span><span>B) -3x -2.25y= -13.5 then adding this to A
</span><span><span>A) 3x + 4y = 17</span>
1.75y = 3.5
y = 2
</span><span>
A) 3x + 4*2 = 17</span>
3x + 8 = 17
3x = 9
x = 3
(3,2)
Answer(1.833,3.167)
Step-by-step explanation:
X=10. so x-3 would be 7. e would equal 7. so 5x7=35
Муну ушундан көбөйтүшүңүз керек, андан кийин эмне болуп жатканын түшүнүш үчүн бөлүң!үз. балким, бул жерде, бул татаал нерсе. сиз тегерек болушуңуз керек, балким, ушул сыяктуу нерсени билип алыңыз?
Doa. :)