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vodomira [7]
3 years ago
11

What is the solution in both interval and graph form of "x>2 or x>-1"?​

Mathematics
1 answer:
tangare [24]3 years ago
6 0

Answer:

Step-by-step explanation:

2>-1

so solution is x>2

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Choose correct response
Illusion [34]

Answer:

D

Step-by-step explanation:

11.1/0.01=11.1*100=1110

7 0
2 years ago
Kat is painting the edge of a triangular stage prop with reflective orange paint. The lengths of the edges of the triangle are (
Eva8 [605]
Plug 4 in for every x

(3*4)-4=8
(4^2)-1=15 [(4^2) is 4*4]
(2*(4^2))-15= 15 [because of PEMDAS the exponent comes first and then multiply by 2 then subtract]

Perimeter is the sum of the lengths so add up all the sides from above
8+15+15=38
3 0
3 years ago
A city has 5 new houses for every 9 old houses. If there are 35 new houses in the city, how many old houses are there?
Nezavi [6.7K]

Answer:

C.) 63

Step-by-step explanation:

You know what you insisted on me answering, so I'll answer here.

35 ÷ 5 = 7

7 x 9 = 63

7 0
3 years ago
Read 2 more answers
15/4 in to equal mixed number
Temka [501]

9514 1404 393

Answer:

  3 3/4

Step-by-step explanation:

  \dfrac{15}{4}=\dfrac{12+3}{4}=\dfrac{12}{4}+\dfrac{3}{4}\\\\=3+\dfrac{3}{4}=\boxed{3\dfrac{3}{4}}

__

The integer part of the mixed number is the quotient when the numerator is divided by the denominator. The remainder from that division is the numerator of the fraction.

  15/4 = 15 ÷ 4 = 3 r 3 = 3 3/4

5 0
3 years ago
On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi
blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

{22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19}  + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069

I hope that works for you!

4 0
3 years ago
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