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3 years ago

I WILL GIVE U 30 POINTS PLEASE ANSWER CORRECTLY

Mathematics

2 answers:

Korolek [52]3 years ago

8 0

Answer:

It will take 7 weeks for Michael to reach his goal.

Step-by-step explanation:

600=50(1.5)^x

12=1.5^x

x≈6.13

Yuliya22 [10]3 years ago

5 0

Answer:

Sssssnake ssssssnake sssssnake...........................................................................................................................................................

Step-by-step explanation:

You might be interested in

A. find the area b. find the perimeter

Allushta [10]

Answer:

Area= 4y^2 + 14y + 12

Perimeter = 10y + 16

Step-by-step explanation:

Area of a reactangle = length × width

= (4y+6) × (y+2)

= 4y^2 + 6y + 8y + 12

= 4y^2 + 14y + 12

Perimeter of a rectangle = 2 × (a +b)

= 2 × ( 4y + 6 + y+ 2)

= 2 × ( 5y + 8)

= 10y + 16

8 0

3 years ago

Five numbers has a mean of 12. When one (1) number is removed the mean is 11. What is the value of the number removed?

bonufazy [111]

Answer:

Step-by-step explanation:

The mean of a group of values is calculated as

mean = $\frac{sum}{count}$

Given 5 numbers with a mean of 12, then

$\frac{sum}{5}$ = 12 ( multiply both sides by 5 )

sum = 60

let the number removed be x , then

$\frac{60-x}{4}$ = 11 ( multiply both sides by 4 )

60 - x = 44 ( subtract 60 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

The number removed was 16

6 0

3 years ago

A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten

AfilCa [17]

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle $\triangle PQR$ where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And $\angle Q \neq 90^\circ$

Given that:

PQ = 44 ft

PR = 51 ft

$\angle R = 58^\circ$

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ$

Now,

$\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ$

Let us use the Sine rule again:

$\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft$