Witch answer choice represents a person running 90 calories by climbing 18 flights of stairs

What expression is 3(x-6)2 - 2(x-1) equivalent to ?

hjlf

Answer:

4x-34

Step-by-step explanation: simplify to find your answer

5 0

3 years ago

Bread and sugar cost 110 together,bread cost 100 more than sugar,how much does sugar cost?

dangina [55]

First write an equation system based on the problem
We can write "Bread and sugar cost 110 together" as
∴ b + s = 110
We can write "bread cost 100 more than sugar" as
∴ b = 100 + s

Second, solve the equation system by subtitution method
Subtitute b with (100+s) in the first equation, and we'll find the value of s
b + s = 110
(100 + s) + s = 110
100 + 2s = 110
2s = 110 - 100
2s = 10
s = 10/2
s = 5
The cost of the sugar is 5

4 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

4 years ago

How do you solve this problem

MArishka [77]

Answer:

1250 p² x¹² y³z⁶m⁵

Step-by-step explanation:

5x²y³z⁵m²(-2p²m³zx⁴)(-5x²)³

5x²y³z⁵m²(-2p²m³zx⁴)(-125x⁶)

5x²y³z⁵m²(250p²m³zx¹⁰)

1250 p²x¹²y³z⁶m⁵