Answer:
∠ C = ∠BCD = 30°
Step-by-step explanation:
∠ EDF = ∠GFC = 110° [ corresponding angles ]
Now consider triangle BCF
∠FBC + ∠ABC = 180° [ straight line angle ]
∠FBC + 100° = 180°
∠FBC = 180 - 100 = 80°
∠BFC + ∠GFC = 180° [ straight line angle ]
∠BFC + 110° = 180°
∠BFC = 180 - 110 = 70°
Sum of angles of triangle is 180°
Therefore , in triangle BCF
That is ,
∠F + ∠B + ∠ C = 180°
70° + 80° + ∠C = 180°
∠C = 180 - 150 = 30°
3) 0.5(12m-22n)=0.5(12m)-0.5(22n)
=6m-11n
4) 2/3(18x+6z) =2/3(18x)-2/3(6z)
=12x-4z
5)2x+12=2(x+6)
6)12x+24=12(x+2)
3·m - 2/3 - 2·m + 1/4 = 2/12
m - 2/3 + 1/4 = 2/12
m = 2/12 - 3/12 + 8/12
m = 7/12